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8a^2-35a-25=0
a = 8; b = -35; c = -25;
Δ = b2-4ac
Δ = -352-4·8·(-25)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2025}=45$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-45}{2*8}=\frac{-10}{16} =-5/8 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+45}{2*8}=\frac{80}{16} =5 $
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